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Maths question for Greedy Thump and others.
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By (user no longer on site) OP
over a year ago
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How many people would need to be in any random grouping, so that an each way bet (ie my £10 v your £10) that at least two people share the same date of birth ( not year though) would be worthwhile? |
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By (user no longer on site)
over a year ago
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"
How many people would need to be in any random grouping, so that an each way bet (ie my £10 v your £10) that at least two people share the same date of birth ( not year though) would be worthwhile?"
Oh come on..I can't be expected to know that?...   |
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By *icketysplitsWoman
over a year ago
Way over Yonder, that's where I'm bound |
You only need a relatively small number of people to get a likelihood of sharing the birthday (not the birth date). I heard a programme on R4 years ago but I can't remember the number.
I do know that when I ran an organisation with 28 staff two of them shared my birthday.
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By (user no longer on site) OP
over a year ago
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"What the fuck????"
Put it this way, if you and i walked into a pub with 35 people in it, and i bet you £10 that at least two people would share the same birthday, would you accept the bet? |
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By *icketysplitsWoman
over a year ago
Way over Yonder, that's where I'm bound |
"I seem to remember reading somewhere that it'd be about 30 folk...can't remember the reasoning behind that though"
It is a number like that and I sort of understood it when it was explained on the R4 but it's all too clever for me to hold in my funny brain.
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By (user no longer on site)
over a year ago
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"Why Greedy ????
Cos on another thread he mentions a (maths) question about 66 handshakes.
"
Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben ) |
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By (user no longer on site)
over a year ago
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"Why Greedy ????
Cos on another thread he mentions a (maths) question about 66 handshakes.
Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben ) "
you can fuxx off now |
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By (user no longer on site)
over a year ago
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When I worked for a high street bank, part of the way data arrived in HR files was to sort all staff by birthday. It was striking in a sample of the population like that just how many people shared the same date.
Btw, to me, we were staff. Not frickin colleagues or any other such management bull that was used at the time.
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By (user no longer on site)
over a year ago
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"Why Greedy ????
Cos on another thread he mentions a (maths) question about 66 handshakes.
Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben )
you can fuxx off now "
Nah you lurve me really |
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By (user no longer on site)
over a year ago
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"Why Greedy ????
Cos on another thread he mentions a (maths) question about 66 handshakes.
Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben )
you can fuxx off now
Nah you lurve me really "
 |
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By (user no longer on site) OP
over a year ago
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"2 out of 17 at work last year shared same birthday and one of them was me.
bet you a £10 they do next year as well?
Nope cos the guy left  "
What, he's changed his birthday because he's left? I feel a Victor Meldrew moment coming on. |
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By *icketysplitsWoman
over a year ago
Way over Yonder, that's where I'm bound |
"2 out of 17 at work last year shared same birthday and one of them was me.
bet you a £10 they do next year as well?
Nope cos the guy left "
He will still share your birthday unless one of you dies.
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By (user no longer on site)
over a year ago
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"2 out of 17 at work last year shared same birthday and one of them was me.
bet you a £10 they do next year as well?
Nope cos the guy left
He will still share your birthday unless one of you dies.
"
Yes but he won't be part of the how many are needed thingy , that was the original question. |
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By (user no longer on site) OP
over a year ago
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"2 out of 17 at work last year shared same birthday and one of them was me.
bet you a £10 they do next year as well?
Nope cos the guy left
He will still share your birthday unless one of you dies.
Yes but he won't be part of the how many are needed thingy , that was the original question. "
Are we not allowed to ask newer questions part way down? |
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By (user no longer on site)
over a year ago
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"2 out of 17 at work last year shared same birthday and one of them was me.
bet you a £10 they do next year as well?
Nope cos the guy left
He will still share your birthday unless one of you dies.
Yes but he won't be part of the how many are needed thingy , that was the original question.
Are we not allowed to ask newer questions part way down?"
You can ask whatever you want I don't mind |
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By *icketysplitsWoman
over a year ago
Way over Yonder, that's where I'm bound |
"There must be an equation for it. So many days in month x months of year divided by people who wear rubber knickers kind of thing "
There is, there is... if only I could remember what the clever person on R4 said I would tell you.
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By (user no longer on site)
over a year ago
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"
How many people would need to be in any random grouping, so that an each way bet (ie my £10 v your £10) that at least two people share the same date of birth ( not year though) would be worthwhile?"
Possibility... 2
Probability....366
Median.... Somewhere in between... |
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By (user no longer on site)
over a year ago
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Example 3.3 How many people do we need to have in a room to make it a favorable bet (probability of success greater than 1/2) that two people in the room will have the same birthday?
Since there are 365 possible birthdays, it is tempting to guess that we would need about 1/2 this number, or 183. You would surely win this bet. In fact, the number required for a favorable bet is only 23. To show this, we find the probability pr that, in a room with r people, there is no duplication of birthdays; we will have a favorable bet if this probability is less than one half. |
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By (user no longer on site) OP
over a year ago
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"Example 3.3 How many people do we need to have in a room to make it a favorable bet (probability of success greater than 1/2) that two people in the room will have the same birthday?
Since there are 365 possible birthdays, it is tempting to guess that we would need about 1/2 this number, or 183. You would surely win this bet. In fact, the number required for a favorable bet is only 23. To show this, we find the probability pr that, in a room with r people, there is no duplication of birthdays; we will have a favorable bet if this probability is less than one half."
Coconut to the lady. Well done.
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By (user no longer on site)
over a year ago
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"Example 3.3 How many people do we need to have in a room to make it a favorable bet (probability of success greater than 1/2) that two people in the room will have the same birthday?
Since there are 365 possible birthdays, it is tempting to guess that we would need about 1/2 this number, or 183. You would surely win this bet. In fact, the number required for a favorable bet is only 23. To show this, we find the probability pr that, in a room with r people, there is no duplication of birthdays; we will have a favorable bet if this probability is less than one half.
Coconut to the lady. Well done.
"
I asked google |
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